# 1. Introduction

A palindrome is a word, phrase, number, or other sequence of characters that reads the same forward and backward (ignoring spaces, punctuation, and capitalization). Checking for palindromes is a common problem in programming interviews and competitions.

# 2. Problem

The problem is to determine if a given string is a palindrome. The solution needs to handle potential edge cases such as capitalization and spaces to ensure accuracy.

# 3. Solution Steps

1. Normalize the string by converting it to lowercase and removing non-alphanumeric characters.

2. Check if the normalized string is equal to its reverse.

3. Output the result.

# 4. Code Program

``````# Define the function to check for a palindrome
def is_palindrome(s):
# Normalize the string
normalized_string = ''.join(c for c in s.lower() if c.isalnum())
# Check if the string is equal to its reverse
return normalized_string == normalized_string[::-1]

# Given string
input_string = "A man, a plan, a canal: Panama"

# Check if the input_string is a palindrome
palindrome_status = is_palindrome(input_string)

# Print the result
print(f"Is the string a palindrome? {palindrome_status}")
``````

### Output:

```Is the string a palindrome? True
```

### Explanation:

1. The is_palindrome function takes a string s as input.

2. normalized_string is created by filtering s to include only alphanumeric characters, converting it to lowercase for case insensitivity.

3. The == operator checks if normalized_string is the same as its reverse (normalized_string[::-1]).

4. input_string is set to the phrase "A man, a plan, a canal: Panama", which is a well-known palindrome when spacing and punctuation are ignored.

5. palindrome_status receives the boolean result from the is_palindrome function.

6. The final print statement uses an f-string to present the result, indicating the string is a palindrome, denoted by True.