C++ Program to Determine if a Number Is Even or Odd

📘 Premium Read: Access my best content on Medium member-only articles — deep dives into Java, Spring Boot, Microservices, backend architecture, interview preparation, career advice, and industry-standard best practices.

🎓 Top 15 Udemy Courses (80-90% Discount): My Udemy Courses - Ramesh Fadatare — All my Udemy courses are real-time and project oriented courses.

▶️ Subscribe to My YouTube Channel (176K+ subscribers): Java Guides on YouTube

▶️ For AI, ChatGPT, Web, Tech, and Generative AI, subscribe to another channel: Ramesh Fadatare on YouTube

1. Introduction

Often in programming and mathematical challenges, there's a need to determine whether a number is even or odd. In C++, this can be done easily with the help of the modulus operator. In this post, we'll walk through a simple C++ program that makes this determination.

2. Program Overview

Our program will:

1. Prompt the user to input a number.

2. Use the modulus operator to determine if the number is even or odd.

3. Display the result to the user.

3. Code Program

#include<iostream>
using namespace std;

int main() {
    int num;

    cout << "Enter an integer: ";
    cin >> num;

    // Using modulus operator to check remainder
    if(num % 2 == 0) {
        cout << "The number is even." << endl;
    } else {
        cout << "The number is odd." << endl;
    }

    return 0;
}

Output:

Enter an integer: 7
The number is odd.

4. Step By Step Explanation

1. The program starts by asking the user to input an integer using cin.

2. The if statement checks if the number, when divided by 2, gives a remainder of 0 using the modulus operator (%).

3. If the remainder is 0, it means the number is divisible by 2 and is therefore even. Otherwise, the number is odd.

4. The program then displays the result using cout.