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In this guide, you will learn about the Math floor() method in Java programming and how to use it with an example.
1. Math floor() Method Overview
Definition:
The floor() method of Java's Math class returns the largest (closest to positive infinity) double value that is less than or equal to the argument and is equal to a mathematical integer.
Syntax:
Math.floor(a)Parameters:
- a: A double value whose floor value is to be determined.
Key Points:
- If the argument is NaN, positive infinity, or negative infinity, then the result will be NaN, positive infinity, or negative infinity, respectively.
- If the argument value is already equal to a mathematical integer, then the result will be the same as the argument.
- The return type is double, even for whole number results.
2. Math floor() Method Example
public class FloorExample {
public static void main(String[] args) {
double[] values = {42.1, 42.7, -42.1, -42.7};
for (double value : values) {
// Calculate the floor value
double floorValue = Math.floor(value);
System.out.println("Floor value of " + value + ": " + floorValue);
}
// Special case for NaN
System.out.println("Floor value of NaN: " + Math.floor(Double.NaN));
}
}
Output:
Floor value of 42.1: 42.0 Floor value of 42.7: 42.0 Floor value of -42.1: -43.0 Floor value of -42.7: -43.0 Floor value of NaN: NaN
Explanation:
In the example:
1. For 42.1 and 42.7, their floor values are 42.0 because the method rounds down.
2. For negative numbers like -42.1 and -42.7, their floor values move further away from zero, resulting in -43.0.
3. The method returns NaN when passed NaN as an argument, aligning with the principle that operations with NaN generally yield NaN.
Related Java Math class method examples
- Java Math abs() example
- Java Math ceil() example
- Java Math floor() example
- Java Math max() example
- Java Math pow() example
- Java Math sqrt() example
- Java Math random() example
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